Pendulum period calculator

This pendulum period calculator uses T = 2π·√(L/g): it gives the period from the pendulum length and vice versa, plus frequency, maximum speed and the exact correction for large swing angles.

Example: Known value: pendulum length · Pendulum length 1 m · Amplitude (swing angle) 10 ° · Location (gravity): Earth (9.81 m/s²) → Result: T = 2.0102 s · f = 0.4975 Hz · L = 1 m. Source: Wikipedia – Mathematisches Pendel (Periodendauer, Großwinkelkorrektur). Updated: .

m
°
maximum angle from the vertical
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Result

Result
T = 2.0102 s · f = 0.4975 Hz · L = 1 m
Pendulum data
MeasureValueFormula
Pendulum length1 m
Period for small angles2.0064 sT₀ = 2π·√(L/g)
Period at your amplitude2.0102 sT = T₀ / AGM(1, cos(θ₀/2))
Frequency0.4975 Hzf = 1/T
Angular frequency3.1256 rad/sω = 2π/T
Maximum speed at the lowest point0.546 m/sv = √(2gL(1 − cos θ₀))
Period at larger amplitudes
AmplitudeFactor T/T₀Period
5°1.00052.0074 s
10°1.00192.0102 s
20°1.00772.0218 s
30°1.01742.0413 s
45°1.042.0866 s
60°1.07322.1532 s
90°1.18032.3682 s
120°1.37292.7546 s
150°1.76223.5357 s
170°2.43944.8944 s
Calculated with g = 9.81 m/s². At your amplitude one swing takes 0.19 % longer than the small-angle formula says. String mass and friction are ignored.

How it is calculated

For small swings, T = 2π·√(L/g). A 1 m pendulum has a period of 2.006 s on Earth, and a seconds pendulum with T = 2 s is about 99.4 cm long.

What the formula says

The period depends only on length and gravity, not on the mass of the bob. Four times the length means twice the period. On the Moon, where g = 1.62 m/s², the same pendulum swings about 2.5 times slower than on Earth.

Large angles

The approximation is only exact for small angles. With a larger amplitude the swing slows down: at 10° the period is 0.2 % longer, at 30° about 1.7 %, at 90° already 18 %. The calculator therefore uses the exact solution with the elliptic integral, computed through the arithmetic-geometric mean: T = T₀ / AGM(1, cos(θ₀/2)).

Frequently asked questions

How do you calculate the period of a simple pendulum?

With T = 2π·√(L/g). For L = 1 m and g = 9.81 m/s² that gives 2.006 s. The mass does not matter.

How long is a seconds pendulum?

A pendulum with a 2 s period (one second per swing) is about 0.994 m long on Earth.

When does the small-angle approximation stop working?

At 20° the error is already about 0.8 %. The calculator therefore shows the correction factor for larger angles in a table.

Sources and legal basis

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