Inductance Calculator

This inductance calculator finds L from the number of turns and the dimensions for air-core coils, toroids and cores with an AL value. Example: an air-core coil with 500 turns, 20 mm diameter and 100 mm length has about 0.90 mH.

Example: What do you want to calculate: Cylindrical coil (air core) · Coil diameter 20 mm · Coil length 100 mm · Number of turns N 500 · Core factor µr 1 · Frequency for the reactance 100 kHz → Result: L ≈ 902.98 µH (Wheeler); ideal long solenoid: 986.96 µH. Source: Wikipedia – Spule (Elektrotechnik), Induktivität. Updated: .

mm
mm
1 for air; for a core that fills the whole coil, the permeability of the core.
kHz
This frequency is used for the reactance X_L = 2π·f·L; 0 hides it.
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Result

Result
L ≈ 902.98 µH (Wheeler); ideal long solenoid: 986.96 µH
Values
ItemValue
Inductance, ideal long solenoid986.96 µH
Inductance, air-core coil by Wheeler902.98 µH
Reactance at 100 kHz567.36 Ω
Turn density5 /mm
Steps
  • Ideal long solenoid: L = µ₀·µr·N²·A / l = µ₀·1·500²·314.16 mm² / 100 mm = 986.96 µH.
  • Wheeler (air core, inches): L[µH] = N²·r² / (9r + 10l) with r = 0.3937 in, l = 3.937 in gives 902.98 µH.
For single-layer air-core coils the Wheeler approximation is more accurate than the ideal formula because it accounts for end effects. Multi-layer windings and thick wire deviate.

How it is calculated

The inductance L of a coil describes how much magnetic flux it produces per ampere; it grows with the square of the number of turns. It is given in henry (H), usually in millihenry or microhenry. The calculator covers four typical cases.

The formulas

For a long cylindrical coil, L = µ₀·µr·N²·A / l, with the number of turns N, cross-section A, length l and the magnetic constant µ₀ = 1.2566·10⁻⁶ H/m. For short single-layer air-core coils the Wheeler approximation L[µH] = N²·r² / (9r + 10l), with r and l in inches, gives better values. A toroidal coil has L = µ₀·µr·N²·A / l with A = h·(Do − Di) / 2 and l = π·(Do + Di) / 2. For cores with an AL value simply L = AL·N²; conversely you need N = √(L / AL) turns.

Example and reactance

The air-core coil with 500 turns, 20 mm diameter and 100 mm length gives 0.99 mH by the ideal formula and 0.90 mH by Wheeler. At 100 kHz that is a reactance X_L = 2π·f·L of about 567 Ω. With an AL value of 1000 nH, 30 turns give 900 µH, and 900 µH also needs 30 turns.

Frequently asked questions

How do you calculate the inductance of a coil?

For a long coil with L = µ₀·µr·N²·A / l. With 500 turns, 20 mm diameter and 100 mm length that is about 0.99 mH without a core; short coils are better calculated by Wheeler.

How many turns do I need for a given inductance?

With the core’s AL value: N = √(L / AL). For 900 µH at AL = 1000 nH that is 30 turns. Without an AL value, rearrange the coil formula for N.

What is the AL value?

The AL value tells which inductance a core gives per turn squared, usually in nH. It combines core material and shape and is in the datasheet.

Sources and legal basis

As of: · Editorial policy

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