RC filter cutoff frequency calculator

This RC filter cutoff frequency calculator uses f = 1/(2π·R·C) from resistance and capacitance, shows the time constant and frequency response, and also handles RL filters and LC resonant circuits.

Example: Which circuit: RC filter (resistor and capacitor) · Resistance R 1 · Resistance R (unit): kΩ · Capacitance C 100 · Capacitance C (unit): nF → Result: Cutoff frequency = 1.5915 kHz · τ = 100 µs. Source: Wikipedia – Tiefpass (cutoff frequency, time constant of RC and RL circuits). Updated: .

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Result

Result
Cutoff frequency = 1.5915 kHz · τ = 100 µs
Key values
MeasureValueFormula
Cutoff frequency1.5915 kHzf_g = 1/(2π·R·C)
Angular frequency10,000 rad/sω = 1/(R·C)
Time constant τ100 µsτ = R·C
Settling time (5·τ)500 µs5·τ
Frequency response (multiples of the cutoff frequency)
FrequencyLow-passHigh-passPhase (low-pass)
159.1549 Hz-0.04 dB-20.04 dB-5.7°
795.7747 Hz-0.97 dB-6.99 dB-26.6°
1.5915 kHz-3.01 dB-3.01 dB-45°
3.1831 kHz-6.99 dB-0.97 dB-63.4°
7.9577 kHz-14.15 dB-0.17 dB-78.7°
15.9155 kHz-20.04 dB-0.04 dB-84.3°
At 1.5915 kHz the low-pass is down 3 dB (factor 0.707) and the phase is 45°. The high-pass is the mirror image: it passes high frequencies and blocks low ones.

How it is calculated

The cutoff frequency of an RC filter is f = 1 / (2π·R·C). With 1 kΩ and 100 nF that is 1,591.5 Hz, and the time constant is 100 µs.

What the cutoff frequency means

At the cutoff frequency the output voltage has fallen to 1/√2 (about 71 %), which is −3 dB. A low-pass passes everything below and attenuates above, a high-pass does the opposite. In an RC filter the low-pass output is taken across the capacitor and the high-pass output across the resistor. The time constant τ = R·C says how fast the capacitor charges: after 5·τ it has reached more than 99 %.

RL filters and resonant circuits

Example: a 10 mH coil and a 100 nF capacitor resonate at 5.03 kHz with a characteristic impedance of 316 Ω.

Frequently asked questions

How do you calculate the cutoff frequency of an RC filter?

With f = 1/(2π·R·C). For R = 1 kΩ and C = 100 nF that gives about 1.59 kHz.

How do you calculate the resonant frequency of an LC circuit?

With Thomson’s formula f₀ = 1/(2π·√(L·C)). For L = 10 mH and C = 100 nF that is about 5.03 kHz.

What is the time constant?

τ = R·C for an RC filter and τ = L/R for an RL filter. After one time constant the capacitor has reached 63 % of the final voltage, after five more than 99 %.

Sources and legal basis

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