Unit Circle Calculator

This unit circle calculator shows the point (cos θ | sin θ) on the circle of radius 1 for any angle. Example: at 150° the point is (−0.866025 | 0.5) and tan θ = −0.57735, in the second quadrant.

Source: Wikipedia – Unit circle. Updated: .

Any number, also negative or above 360°.
My ToolboxYour inputs are saved in this browser only.

Result

Result
θ = 150° → point P(-0.866025 | 0.5), tan θ = -0.57735 (quadrant II)
All values
QuantityValue
Angle between 0° and 360°150°
Radians2.61799
Positionquadrant II
sin θ (y-coordinate)0.5
cos θ (x-coordinate)-0.866025
tan θ = sin θ / cos θ-0.57735
Exact (sin | cos | tan)1/2 | −√3/2 | −√3/3
Calculation steps
  • Reference angle (acute angle to the x-axis): 30°; signs in this position: sin +, cos −.
  • sin θ = 0.5, cos θ = -0.866025, tan θ = sin θ / cos θ = -0.57735.
  • Exact values: sin θ = 1/2, cos θ = −√3/2, tan θ = −√3/3.
The point lies on the circle of radius 1, so sin²θ + cos²θ = 1. At 90° and 270° cos θ = 0, so the tangent is not defined.

How it is calculated

The unit circle is the circle of radius 1 around the origin. Every angle θ, measured from the positive x-axis counter-clockwise, belongs to a point P(cos θ | sin θ).

How to read the unit circle

The x-coordinate of the point is the cosine, the y-coordinate the sine. The tangent is the ratio sin θ / cos θ, the slope of the segment from the origin to the point. Angles above 360° or below 0° are reduced by full turns. The signs depend on the quadrant: in I sine and cosine are positive, in II cosine is negative, in III both, in IV only sine.

Worked example

For θ = 150° the point lies in the second quadrant; the reference angle is 180° − 150° = 30°. With sin 30° = 1/2 and cos 30° = √3/2, it follows that sin 150° = 1/2 = 0.5 and cos 150° = −√3/2 = −0.866025. The tangent is −√3/3 = −0.57735. The point is therefore P(−0.866025 | 0.5). The calculator also gives the exact values when the angle is a multiple of 30° or 45°.

Frequently asked questions

What does the unit circle show?

For every angle it shows sine and cosine as the coordinates of a point on the circle of radius 1. At 150° that is P(−0.866025 | 0.5).

How do you find the signs of sine and cosine?

From the quadrant: in the second quadrant (90° to 180°) sine is positive and cosine is negative.

Why is the tangent not defined at 90°?

Because cos 90° = 0 and the tangent sin θ / cos θ would need a division by zero.

Sources and legal basis

As of: · Editorial policy

Related tools