Average Rate of Change Calculator

This average rate of change calculator works for a function ax² + bx + c on an interval or for two points. Example: f(x) = x² between x = 1 and x = 4 has an average rate of change of (16 − 1) / 3 = 5.

Source: Wikipedia – Differenzenquotient. Updated: .

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Result

Result
Average rate of change m = 5 (from x = 1 to x = 4: Δy = 15, Δx = 3)
All values
QuantityValue
Point 1(1 | 1)
Point 2(4 | 16)
Change Δx3
Change Δy15
Average rate of change m5
Secant liney = 5·x − 4
Calculation steps
  • Function values: f(1) = 1 and f(4) = 16.
  • m = Δy / Δx = (y₂ − y₁) / (x₂ − x₁) = (16 − 1) / (4 − 1) = 15 / 3 = 5.
  • Secant through both points: y = m·x + n with n = y₁ − m·x₁ = 1 − 5·1 = -4, so y = 5·x − 4.
On average the values rise: y grows by m per unit of x.

How it is calculated

The average rate of change tells you how much a quantity changes per unit on average, and it equals the slope of the secant line through two points of the graph. It is also called the difference quotient and is the forerunner of the derivative.

Formula and steps

For two points (x₁, y₁) and (x₂, y₂), m = Δy / Δx = (y₂ − y₁) / (x₂ − x₁). For a function, first compute f(x₁) and f(x₂) and use them as the y-values. The calculator also gives the secant equation y = m·x + n. The order of the two points does not matter as long as x and y are swapped together.

Examples

For f(x) = x² on [1, 4], f(1) = 1 and f(4) = 16, so m = 15 / 3 = 5 and the secant is y = 5x − 4. The points (1, 3) and (4, 12) give m = 9 / 3 = 3 and y = 3x. An everyday case: a car covering 240 km in 3 hours has an average rate of change of distance of 80 km/h.

Frequently asked questions

What is the difference between average and instantaneous rate of change?

The average rate applies to a whole interval and is the secant slope. The instantaneous rate applies at a single point and is the tangent slope, that is, the derivative.

How do I find the average rate of change of a function?

Compute f(x₂) − f(x₁) and divide by x₂ − x₁. For f(x) = x² between 1 and 4 that gives (16 − 1) / 3 = 5.

Can the average rate of change be negative?

Yes, when the values fall over the interval. The secant then slopes downward and m is below 0.

Sources and legal basis

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