Carnot Efficiency Calculator

This Carnot efficiency calculator gives the highest possible efficiency of a heat engine working between a hot and a cold reservoir: e = 1 − Tc/Th, with temperatures in kelvin. Between 750 K and 300 K it is 60 %. It also shows the coefficients of performance of a Carnot refrigerator and heat pump and the heat flows per cycle.

Example: Known values: Both temperatures · Temperature unit: Kelvin (K) · Hot reservoir Th 750 · Cold reservoir Tc 300 · Energy per cycle: Work W done by the engine · Amount of energy 300 J → Carnot efficiency: Efficiency 60.0 % · fridge COP 0.67 · heat pump COP 1.67. Source: OpenStax University Physics Volume 2, 4.5 The Carnot Cycle – e = 1 − Tc/Th (Eq. 4.5), K_R = Tc/(Th − Tc) (Eq. 4.6), K_P = Th/(Th − Tc) (Eq. 4.7), W = Qh − Qc, Carnot’s principle; Example 4.2 (e = 0.60, Tc = 300 K → Th = 750 K, W = 300 J → Qh = 500 J, Qc = 200 J), Example 4.3 (heat pump 0 °C/20 °C, 30.0 kJ → about 2 kJ) (read 10.10.2026). Updated: .

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Result

Carnot efficiency
Efficiency 60.0 % · fridge COP 0.67 · heat pump COP 1.67
Working
QuantityValue
Hot reservoir Th750.00 K = 476.85 °C
Cold reservoir Tc300.00 K = 26.85 °C
Efficiency e = 1 − Tc/Th1 − 300.00 ÷ 750.00 = 0.6000 = 60.0 %
Refrigerator K_R = Tc/(Th − Tc)300.00 ÷ (750.00 − 300.00) = 0.67
Heat pump K_P = Th/(Th − Tc)750.00 ÷ (750.00 − 300.00) = 1.67
Work W300.00 J
Heat at the hot side Qh500.00 J
Heat at the cold side Qc200.00 J
Calculated for an ideal, reversible Carnot cycle with T in kelvin (T = t + 273.15). Real machines between the same temperatures reach less. Engine: Qh = W/e, Qc = Qh − W.

How it is calculated

The Carnot efficiency is e = 1 − Tc/Th, where Th and Tc are the absolute temperatures (in kelvin) of the hot and the cold reservoir. The textbook OpenStax University Physics derives this formula for the Carnot cycle – two isothermal and two adiabatic steps – and states Carnot’s principle: no engine working between two reservoirs at constant temperatures can be more efficient than a reversible engine. The Carnot efficiency is therefore an upper limit, not the efficiency of a real engine.

Carnot efficiency for typical temperatures

Hot (°C)Cold (°C)Efficiency eFridge K_RHeat pump K_P
100010070.7 %0.411.41
6003065.3 %0.531.53
4003055.0 %0.821.82
1002021.4 %3.664.66
3559.7 %9.2710.27
2508.4 %10.9311.93
2006.8 %13.6614.66

The temperatures must be converted to kelvin first (T = t + 273.15): between 400 °C and 30 °C, e = 1 − 303.15/673.15 = 0.550. OpenStax Example 4.2 works backwards: an efficiency of 0.60 with a cold reservoir at 300 K needs Th = 300 K ÷ (1 − 0.60) = 750 K. If that engine does 300 J of work per cycle, it takes Qh = W/e = 500 J from the hot reservoir and gives off Qc = 500 J − 300 J = 200 J.

Refrigerator and heat pump

Run in reverse, the Carnot cycle is a refrigerator or a heat pump. Their coefficients of performance are K_R = Tc/(Th − Tc) for the refrigerator and K_P = Th/(Th − Tc) for the heat pump; both grow when the two temperatures are close together. In Example 4.3 a Carnot heat pump delivers 30.0 kJ into a house at 20 °C from outside air at 0 °C. It needs W = 30 kJ × (293 K − 273 K)/293 K, which the book rounds to 2 kJ; with 273.15 the calculator shows 2.05 kJ. The colder it is outside, the smaller K_P and the more work is needed.

The energy needed to heat water is found with the energy to heat water calculator; work and kinetic energy are covered by the kinetic energy calculator.

Frequently asked questions

What is the formula for Carnot efficiency?

e = 1 − Tc/Th, with Th and Tc the temperatures of the hot and cold reservoir in kelvin. Multiply by 100 for percent.

What is the Carnot efficiency between 400 °C and 30 °C?

In kelvin: 673.15 K and 303.15 K. e = 1 − 303.15/673.15 = 0.550, so 55.0 %.

Why do I have to use kelvin?

The formula uses the ratio of absolute temperatures. With degrees Celsius the ratio is wrong – and a cold side at 0 °C would give 100 %.

Can a real engine reach the Carnot efficiency?

No. Carnot’s principle says that no engine between two reservoirs is more efficient than a reversible one; real engines lose energy and stay below the limit.

What is the COP of a Carnot refrigerator?

K_R = Tc/(Th − Tc). For a fridge between 0 °C and 25 °C: 273.15/25 = 10.93. A heat pump between the same temperatures reaches K_P = Th/(Th − Tc) = 11.93.

Sources and legal basis

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