Normal Force Calculator

This normal force calculator finds the force with which a surface pushes perpendicular to a body. Example: 10 kg on a plane inclined at 30° gives N ≈ 84.93 N.

Example: Mass m 10 kg · Slope angle θ 30 ° · Gravitational acceleration g 9.8067 m/s² · Extra force perpendicular to the surface 0 N → Result: Normal force N = 84.9281 N (weight 98.0665 N). Source: NIST – Standard acceleration of gravity g_n = 9,80665 m/s² (exakt, CGPM 1901). Updated: .

kg
°
0° = horizontal, 90° = vertical wall.
m/s²
Standard value 9.80665 m/s² (exact, CGPM 1901).
N
Positive: presses onto the surface; negative: pulls away from it. Empty = 0.
For the maximum static friction μ·N; 0 = not shown.
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Result

Result
Normal force N = 84.9281 N (weight 98.0665 N)
Forces at a glance
ForceValue
Weight F_G98.0665 N
Normal force N84.9281 N
Force down the slope49.0332 N
Calculation steps
  • Weight F_G = m·g = 10·9.80665 = 98.0665 N.
  • Normal force N = F_G·cos θ = 98.0665·cos(30°) = 84.9281 N.
  • Force down the slope = F_G·sin θ = 98.0665·sin(30°) = 49.0332 N.
The normal force is perpendicular to the surface; on a slope it is smaller than the weight. Calculated for a body at rest on a flat, rigid surface.

How it is calculated

The normal force is the force with which a support pushes perpendicular to a body resting on it. It always acts at right angles (“normal”) to the contact surface and stops the body from sinking into it. It is not automatically equal to the weight.

Formula

On a plane inclined at the angle θ, N = m·g·cos θ. In addition, the component m·g·sin θ acts along the surface, down the slope. If another force presses or pulls perpendicular to the surface, it is added (a pull counts as negative). The maximum static friction is μ·N. The standard value g = 9.80665 m/s² is used for gravity.

Worked example

A 10 kg body rests on a plane inclined at 30°. Weight: 10 · 9.80665 = 98.0665 N. Normal force: 98.0665 · cos 30° ≈ 84.93 N. Force down the slope: 98.0665 · sin 30° ≈ 49.03 N. On a horizontal surface (0°) N = 98.0665 N, on a vertical wall (90°) it is 0.

Frequently asked questions

How do you calculate the normal force?

On an inclined plane with N = m·g·cos θ. On a horizontal surface this is simply N = m·g.

Why is the normal force on a slope smaller than the weight?

Only the component of the weight perpendicular to the surface (cos θ) is carried by the surface; the rest (sin θ) acts along the surface as the force down the slope.

How is friction related to the normal force?

The maximum static friction is μ·N. The larger the normal force, the larger the possible friction force.

Sources and legal basis

As of: · Editorial policy

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